1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1

  1. c.
    6 x^2 + 11x– 2 = 6x^2 – x+ 12x– 2 = (6x^2 – x) +
    (12x– 2) = x(6x– 1) + 2(6x– 1) = (x+ 2)(6x– 1)

  2. b.
    12 x^2 – 37x– 10 = 12x^2 + 3x– 40x– 10 = 3x(4x





    1. – 10(4x+ 1) = (3x– 10)(4x+ 1)





  1. c.
    7 x^2 – 12x+ 5 = 7x^2 – 5x– 7x+ 5 = x(7x– 5) –
    (7x– 5) = (7x– 5)(x– 1)

  2. a.
    9 – 7x– 2x^2 = 9 + 2x– 9x– 2x^2 = 1(9 + 2x) –
    x(9 + 2x) = (9 + 2x)(1 – x)

  3. c.
    2 x^3 + 6x^2 + 4x= 2x(x^2 + 3x+ 2) =
    2 x(x^2 + x+ 2x+ 2)


= 2 x(x(x+ 1) + 2(x+ 1) = 2x(x+ 2)(x+ 1)


  1. c.
    –4x^5 + 24x^4 – 20x^3 = –4x^3 (x^2 – 6x+ 5) =
    –4x^3 (x^2 – x– 5x+ 5)


= –4x^3 (x(x– 1) – 5(x–1)) = –4x^3 (x– 5)(x–1)


  1. b.
    –27x^4 + 27x^3 – 6x^2 = –3x^2 (9x^2 – 9x+ 2) =
    –3x^2 (9x^2 – 6x– 3x+ 2)


= –3x^2 [(9x^2 –6x) – (3x– 2)] = –3x^2 [3x(3x– 2)


  • (3x– 2)] = –3x^2 (3x– 1)(3x– 2)



  1. b.
    x^2 (x+ 1) – 5x(x+ 1) + 6(x+ 1) = (x+ 1)(x^2 –
    5 x+ 6) = (x+ 1)(x^2 – 2x– 3x+ 6)


= (x+ 1)[x(x– 2) – 3(x– 2)] = (x+ 1)(x– 3)
(x– 2)


  1. a.
    2 x^2 (x^2 – 4) – x(x^2 – 4) + (4 – x^2 ) = 2x^2 (x^2 – 4) –
    x(x^2 – 4) – (x^2 – 4) = (x^2 – 4)[2x^2 – x– 1]
    = (x^2 – 4)[2x^2 – 2x+ x– 1] = (x^2 – 4)[2x(x– 1)


+ (x–1)] = (x^2 – 4)(2x+ 1)(x– 1)
= (x– 2)(x+ 2)(2x+ 1)(x– 1)
428. b.

27(x– 3) + 6x(x– 3) – x^2 (x– 3) = (x– 3)(27 +
6 x– x^2 ) = (x– 3)(27 + 6x+ x^2 )

= –(x– 3)(x^2 – 6x– 27) = –(x– 3)(x^2 – 9x+ 3x




    1. = –(x– 3)(x(x– 9) + 3(x– 9))




= –(x– 3)(x+ 3)(x– 9)


  1. c.
    (x^2 + 4x+ 3)x^2 + (x^2 + 4x+ 3)3x+ 2(x^2 + 4x+


3) = (x^2 + 4x+ 3)[x^2 + 3x+ 2]

= (x^2 + 3x+ x+ 3)[x^2 + x+ 2x+ 2] = (x(x+
3) + (x+ 3))[x(x+ 1) + 2(x+ 1)]

= ((x+ 1)(x+ 3))[(x+ 2)(x+ 1)] = (x+ 1)^2 (x
+ 2)(x+ 3)


  1. a.
    18(x^2 + 6x+ 8) – 2x^2 (x^2 + 6x+ 8) = (x^2 + 6x+
    8)[18 – 2x^2 ] = (x^2 + 6x+ 8)[2(9 – x^2 )]


= (x^2 + 4x+ 2x+ 8)[2(3^2 – x^2 )] = (x(x+ 4)
+2(x+ 4))[2(3 – x)(3 + x)]

= 2(x+ 2)(x+ 4)(3 – x)(3 + x)


  1. a.
    2 x^2 (16 + x^4 ) + 3x(16 + x^4 ) = (16 + x^4 ) = (16 +
    x^4 )[2x^2 + 3x+ 1]


= (16 + x^4 )[2x^2 + 2x+ x+ 1] = (16 + x^4 )[2x(x
+ 1) + (x+ 1)] = (16 + x^4 )(2x+ 1)(x+ 1)


  1. a.
    6 x^2 (1 – x^4 ) + 13x(1 – x^4 ) + 6(1 – x^4 ) = (1 – x^4 )
    [6x^2 + 13x+ 6] = (1 – x^4 )[6x^2 + 4x+ 9x+ 6]


= (1^2 – (x^2 )^2 )[2x(3x+ 2) + 3(3x+ 2)] =
(1 – x^2 )(1 + x^2 )(2x+ 3)(3x+ 2)

= (1 – x)(1 + x)(1 + x^2 )(2x+ 3)(3x+ 2)

ANSWERS & EXPLANATIONS–
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