1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1

  1. d.The sum G + Ais not defined because Gand Ahave different dimensions. So, this entire computation
    is not well-defined.

  2. d.The product FEis not defined because the inner dimensions ofFand Eare not the same. Therefore,
    this entire computation is not well-defined.

  3. a. 8(CCCF) 


...



  1. c.First, we insert the actual matrices into the expression:


....


Note that both products enclosed by parentheses are well-defined when computed from left to right
since the inner dimensions are the same for each product to be computed. Moreover, the product
enclosed in the first set of parentheses results in a real number:

...


The original product becomes 0. , which is simplified as follows: 0.


  1. b.


3 D– 2AB+ GH

..


=


9


5


4


1


3


2


1


1


2


10


17


9


17


14


5


2


7


0







+=–


R


T


S


S


SS


R


T


S


S


S


S


V


X


W


W


WW


V


X


W


W


W


W


9


0


3


6


3


3


3


6


0


10


12


8


24


20


6


2


0


–– 2








=+


R


T


S


S


SS


R


T


S


S


SS


V


X


W


W


WW


V


X


W


W


WW


9


0


3


6


3


3


3


6


0


2


5


6


4


12


10


3


1


0


1


9


5


4


1


3


2


1


1


–– 2



––



+ –


R


T


S


S


S


S


R


T


S


S


S


S


R


T


S


S


SS


V


X


W


W


W


W


V


X


W


W


W


W


V


X


W


W


WW


3


1


0


2


1


2


0


1


1


1


2


– 0





R


T


S


S


S


S


S


V


X


W


W


W


W


W


2


1


1


1


2


1


0


1


2


1


0


1








––


+


R


T


S


S


SS


V


X


W


W


WW


1


3


2


5


1


0


3 30 > ––H


1


2


1


1


1


2


0


2


1


0


1


2


2


–– 1




––


=


R


T


S


S


SS


R


T


S


S


SS


V


X


W


W


WW


V


X


W


W


WW


(^00) == 0 >> (^00) HH (^00)


N


P


O


O


OO


> H


0


1


1


>N – 4 H


P


O


O


OO


0


0


N


P


O


O


OO


(^0) > H
1


1


>N – 4 H


P


O


O


OO


0


0


= 9412 – C> 0 H=


0


> 0 H


1


0


1


2


2


1



––


R


T


S


S


SS


V


X


W


W


WW


9 –– 420 C


0


0


N


P


O


O


OO


> H


0


1


1


>N – 4 H


P


O


O


OO


0


0


N


P


O


O


OO


> H


1


0


1


2


2


1



––


R


T


S


S


SS


V


X


W


W


WW


()()EAF CF = –– 420


J


L


K


K


KK


9 C


8


0


0


0


==>>HH 0


0


8 > 0 Hp

4


17


17


72



= f> – H

0


> 0 Hp

0


1


1


> – 4 H


= (^8) f>–^14 – 174 H


0


> 0 Hp

0


1


1


> – 4 H


0


1


1


> – 4 H


8 0


1


1


– 4


(2 ) (2 ) (2 )CCCF= = f> H

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