1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1

  1. b.First, we rewrite the system by moving all
    variable terms to the left sides of the equations
    and all constant terms to the right sides to
    obtain the following equivalent system:


Now, extract the coefficients from the variable
terms on the left sides of the equations to form
a 2 2 coefficient matrix. Multiplying this by




x
yand identifying the right side as a 2^1
constant matrix, we can rewrite this system as
the following matrix equation:


  1. b.First, we rewrite the system by moving all
    variable terms to the left sides of the equations
    and all constant terms to the right sides to
    obtain the following equivalent system:


Now, extract the coefficients from the variable
terms on the left sides of the equations to form
a 2 2 coefficient matrix. Multiplying this by




x
yand identifying the right side as a 2^1
constant matrix, we can rewrite this system as
the following matrix equation:


  1. a.First, we rewrite the system by moving all
    variable terms to the left sides of the equations
    and all constant terms to the right sides to
    obtain the following equivalent system:


Now, extract the coefficients from the variable
terms on the left sides of the equations to form
a 2 2 coefficient matrix. Multiplying this by




x
yand identifying the right side as a 2^1
constant matrix, we can rewrite this system as
the following matrix equation:


  1. c.Compute the product on the left side to
    write it as a single matrix, and then equate cor-
    responding entries in the matrices on the left
    and right sides of the equation to obtain the
    desired system:


2


21


x
xy

x
xy

x
y

1


2


0


1


2


2


1


2


1







––




=


=


=


>>>=


>>


HH H


HH


*


x
y

0


2


1


1


4


–– 0


>>>HH H= –


y 4
20 xy


––


=


=


*


x
y

2


12


0


3


2


– 4


= –


>>>HH H


22 x
12 xy 3 4



=


* =


x
y

3


1


1


2


5


9



>>>––HH H=


35


29


yy
xy


––


+=


* =


ANSWERS & EXPLANATIONS–
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