Chapter 15: Circles 211
But let’s go back to the distance formula for just
another minute. dxx yy 21 ^2 212. You
know one point is the origin, (0,0), and the dis-
tance is 5. Let’s plug those in.
Now drop the little twos at the bottom of the x
and y, and then square both sides to get rid of the
square root.
Do you know what that is? It’s the equation of the
following circle—a circle with a center at (0,0)
and a radius of 5.
50 0
5
2
2
2
2
2
2
2
2
xy
xy
5
5
25
22
222
22
xy
xy
xy
-6 -2 062
-2
2
4
6
-4
-6
-7 -5 -4 -1-3 -1 134 5 7
-3
-5
-7
1
3
5
7
y
x
The equation of a circle with center (0,0)
and radius r is x^2 + y^2 = r^2.
If the center isn’t at the origin, the equation
gets a little more complicated, but in a way
that makes sense if you remember that it
came from the distance formula. Suppose
you wanted a circle of radius 5 with its
center at (1,4). The equation would be (x –
1)^2 + (y – 4)^2 = 5^2. The equation of a circle
with center at (h,k) and radius r is (x – h)^2 +
(y – k)^2 = r^2.