Algebra Know-It-ALL

(Marvins-Underground-K-12) #1

196 First-Degree Equations in One Variable


The right-hand distributive law for division over addition, applied to the expression on the right side of
the equation, gives us

x=a/2+ (−b)/2+c/2+ (−12)/2

We can simplify the right-hand side by changing all the negative additions back to subtractions, and then
dividing out the numeral quotient. This gives us

x=a/2−b/2+c/2− 6

Products and Ratios


Let’s see what happens when the quantities on either side of an equation are multiplied by
constants, divided by nonzero constants, or both.

Examples
Here are five first-degree equations that contain a variable x multiplied and/or divided by
constants.

4 x= 0
x / 7 = 2
2 x/a=b
5 abx=c
3 x/(4a)= 3

Using the rules from Chap. 9, we can manipulate these equations to get x alone on the left
side, and the constants all by themselves on the right. That solves the equations. Here are the
results.

x= 0
x= 14
x=ab/2
x=c/(5ab)
x= 4 a

Are you confused?
If you can’t see straightaway how these solutions are derived, Tables 12-6 through 12-10 show how
the equations can be solved, step-by-step. Note that in the third and fifth original equations above
(and in Tables 12-8 and 12-10), we must not let a equal 0. Also, in the fourth solution equation (and
in Table 12-9), we must never allow either a or b to equal 0.
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