614 Worked-Out Solutions to Exercises: Chapters 1 to 9
- This S/R proof is shown in Table A-11. We can “legally” take the rth power of both sides
in line 2 of the proof even if r is a reciprocal power. Remember, if there is any positive-
negative ambiguity when taking a reciprocal power, the positive value is the “default.” - We can start by stating the generalized multiplication-of-exponents (GMOE) rule as
it appears in the chapter text. The exponent names are changed to keep us out of a
“rote-memorization rut,” and also to conform to the way the problem is stated. For any
numberx except 0, and for any rational numbers r and s,
(xr)s=xrs
Applying the commutative law for multiplication to the entire exponent on the right-
hand side of this equation, we get
(xr)s=xsr
Finally, we can invoke the GMOE rule “in reverse” to the right-hand side, obtaining
(xr)s= (xs)r
Q.E.D. Mission accomplished!
- Let’s suppose that x is a positive number. It can by any number we want, as long as it is
larger than 0. We take the 4th root or 1/4 power of x, and then square the result. That
gives us
(x1/4)^2
According to the GMOE rule, that is the same as
x(1/4)×^2
Table A-11. Solution to Prob. 7 in Chap. 8. This shows that the
multiplication-of-exponents rule applies to a “power of a power of
a power.” As you read down the left-hand column, each statement is
equal to all the statements above it.
Statements Reasons
(ap)q = apq GMOE rule as given in Chap. 8 text, where a is any
number except 0, and p and q are rational numbers
[(ap)q]r = (apq)r Take rth power of both sides, where r is a rational
number
[(ap)q]r = a(pq)r Consider (pq) as a single quantity and then use
GMOE rule on right-hand side
[(ap)q]r = apqr Ungrouping of products in exponent on right-hand
side
Q.E.D. Mission accomplished