Algebra Know-It-ALL

(Marvins-Underground-K-12) #1
If we add 18z to each side, we get

z+ 18 z≥− 18 z− 18 + 18 z

which simplifies to

19 z≥− 18

We finish by dividing each side by 19. That leaves us with

z≥−18/19

The original inequality holds true for all values of z larger than or equal to −18/19.

Chapter 12



  1. See Table B-1.

  2. See Table B-2.

  3. See Table B-3.


Table B-2. Solution to Prob. 2 in Chap. 12.
Statements Reasons
x/3= 6 x+ 2 This is the equation we are given
x= 3(6x+ 2) Multiply through by 3
x= 18 x+ 6 Distributive law applied to the right side
− 17 x= 6 Subtract 18x from each side
− 17 x− 6 = 0 Subtract 6 from each side
17 x+ 6 = 0 Multiply through by −1 and apply
the distributive law to the right side,
obtaining a more elegant equation

Chapter 12 623

Table B-1. Solution to Prob. 1 in Chap. 12.
Statements Reasons
4x+ 4 = 2x − 2 This is the equation we are given
2 x+ 4 =−2 Subtract 2 x from each side
2 x+ 6 = 0 Add 2 to each side
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