MA 3972-MA-Book April 11, 2018 14:46
182 STEP 4. Review the Knowledge You Need to Score High
200 m
x
y
θ
Camera
Balloon
Figure 9.1-5
Step 1: Letxbe the distance between the balloon and the ground;θbe the camera’s angle
of elevation; andtbe the time in seconds.
Step 2: Given:
dx
dt
=10 m/sec; distance between camera and the point on the ground
where the balloon took off is 200 m, tanθ=
x
200
.
Step 3: Find
dθ
dt
atx=150 m.
Step 4: Differentiate both sides of the equation with respect tot.
sec^2 θ
dθ
dt
=
1
200
dx
dt
;
dθ
dt
=
1
200
(
1
sec^2 θ
)
(10)=
1
20 sec^2 θ
.
Step 5: secθ=
y
200
and atx=150.
Using the Pythagorean Theorem:y^2 =x^2 +(200)^2
y^2 =(150)^2 +(200)^2
y=± 250.
Sincey>0, theny=250. Thus, secθ=
250
200
=
5
4
.
Evaluating
dθ
dt
∣∣
∣
∣x= 150 =
1
20 sec^2 θ
=
1
20
(
5
4
) 2 radian/sec
=
1
20
(
5
4
) 2 =
1
20
(
25
16
)=^1
125
4
=
4
125
radian/sec
or.032 radian/sec
= 1 .833 deg/sec.
Step 6: The camera’s angle of elevation changes at approximately 1.833 deg/sec when the
balloon is 150 m in the air.