154 STEP 4. Review the Knowledge You Need to Score High
200 mxyθCameraBalloonFigure 8.1-5Step 1: Letxbe the distance between the balloon and the ground;θbe the camera’s angle
of elevation; andtbe the time in seconds.
Step 2: Given:
dx
dt
=10 m/sec; distance between camera and the point on the ground
where the balloon took off is 200 m, tanθ=
x
200.
Step 3: Find
dθ
dt
atx=150 m.
Step 4: Differentiate both sides with respect tot.sec^2 θ
dθ
dt=
1
200
dx
dt;
dθ
dt=
1
200
(
1
sec^2 θ)
(10)=1
20 sec^2 θ.
Step 5: secθ=
y
200
and atx=150.Using the Pythagorean Theorem:y^2 =x^2 +(200)^2
y^2 =(150)^2 +(200)^2
y=± 250.Sincey>0, theny=250. Thus, secθ=250
200
=
5
4
.
Evaluating
dθ
dt∣∣
∣
∣x= 150 =1
20 sec^2 θ=
1
20
(
5
4) 2 radian/sec=
1
20
(
5
4) 2 =1
20
(
25
16)=^1
125
4=
4
125
radian/secor.032 radian/sec
= 1 .833 deg/sec.
Step 6: The camera’s angle of elevation changes at approximately 1.833 deg/sec when the
balloon is 150 m in the air.