5 Steps to a 5 AP Calculus BC 2019

(Marvins-Underground-K-12) #1

172 STEP 4. Review the Knowledge You Need to Score High



  1. (a) Summarize the information off′on
    a number line.


.5 2.5
decr. incr.
rel. min

l ′ –+ 0

l

Sincefhas only one relative
extremum, it is the absolute
extremum. Thus, atx=3, it is an
absolute minimum.
(b) The functionfis decreasing on the
interval (−∞, 3) and increasing on
(3,∞).
(c)
f′

f′′
f

++ 3

incr

concave
upward

concave
upward

0 incr

No change of concavity⇒No point
of inflection.
(d) The functionfis concave upward for
the entire domain (−∞,∞).
(e) Possible sketch of the graph forf(x).
(See Figure 8.7-1.)

3

(3,–2)

0 x

y
f

Figure 8.7-1


  1. (Calculator) (See Figure 8.7-2.)


Figure 8.7-2

Step 1: Differentiate:
2 x+ 2 y

dy
dx

= 0 ⇒


dy
dx

=−


x
y

.


Step 2: Set
dy
dx

=− 1 ⇒


−x
y

=− 1 ⇒


y=x.
Step 3: Solve fory:x^2 +y^2 = 36 ⇒
y^2 = 36 −x^2 ;
y=±


36 −x^2.
Step 4: Thus,y=x⇒±


36 −x^2 =
x⇒ 36 −x^2 =x^2 ⇒
36 = 2 x^2 orx=± 3


2.


  1. (Calculator) (See Figure 8.7-3.)


Step 1: Distance formula:
z=


√ (x−1)^2 +(x^3 )^2 =
(x−1)^2 +x^6.

Figure 8.7-3
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