Integration 221
Example 9
Evaluate
∫
x^35 (x
(^4) )
dx.
Step 1. Letu=x^4.
Step 2. Differentiate:du= 4 x^3 dx⇒
du
4
=x^3 dx.
Step 3. Rewrite:
∫
5 u
du
4
=
1
4
∫
5 udu.
Step 4. Integrate:
1
4
( 5 u)/ln 5+C.
Step 5. Replaceu:
5 x^4
4ln5
+C.
Step 6. Differentiate and Check: 5(x
(^4) )(
4 x^3
)
ln 5/(4 ln 5)=x^35 (x
(^4) )
.
Example 10
Evaluate
∫
(sinπx)ecosπxdx.
Step 1. Letu=cosπx.
Step 2. Differentiate:du=−πsinπxdx;−
du
π
=sinπxdx.
Step 3. Rewrite:
∫
eu
(
−du
π
)
=−
1
π
∫
eudu.
Step 4. Integrate:−
1
π
eu+C.
Step 5. Replaceu:−
1
π
ecosπx+C.
Step 6. Differentiate and Check:−
1
π
(ecosπx)(−sinπx)π=(sinπx)ecosπx.
10.3 Techniques of Integration
Main Concepts:Integration by Parts, Integration by Partial Fractions
Integration by Parts
According to the product rule for differentiation
d
dx
(uv)=u
dv
dx
+v
du
dx
. Integrating
tells us thatuv=
∫
u
dv
dx
+
∫
v
du
dx
, and therefore
∫
u
dv
dx
=uv−
∫
v
du
dx
. To inte-
grate a product, careful identification of one factor asu and the other as
dv
dx
allows
the application of this rule for integration by parts. Choice of one factor to be u
(and therefore the other to bedv) is simpler if you remember the mnemonicLIPET.