5 Steps to a 5 AP Chemistry 2019

(Marvins-Underground-K-12) #1

264 ❯ STEP 4. Review the Knowledge You Need to Score High


decay is not a linear process, you cannot use the chart to predict how much would still
be radioactive at the end of 12 days or at some time (or amount) that is not associated with
a multiple of a half-life. To solve these types of problems, one must use the mathematical
relationships associated with first-order kinetics that were presented in the Kinetics chapter.
In general, two equations are used:
−=−
=

AA


tk

(1)ln[ ]ln[ ]
(2)ln2/

to
1/2

kt

In these equations, the ln is the natural logarithm; At is the amount of isotope radioac-
tive at some time t; Ao is the amount initially radioactive; and k is the rate constant for the
decay. If you know initial and final amounts and are looking for the half-life, you would
use equation (1) to solve for the rate constant and then use equation (2) to solve for t1/2.
For example: What is the half-life of a radioisotope that takes 15 min to decay to 90%
of its original activity?
First use equation (1) to determine k, then use the value of k in equation (2) to deter-
mine the half-life:

k
k
k

Usingequation(1):ln90/100 (15min)
0.1054 (15min)
7.02 10 min^31

=−


−=−


×=−−




=


−−
−−

t
t
t

Nowequation(2):ln 2/7.02 10 min
0.693/7.02 10 min
98.7 min

1/2

31

1/2

31

1/2

If one knows the half-life and amount remaining radioactive, equation (2) can be used to
calculate the rate constant k and equation (1) can then be used to solve for the time. This is
the basis of C-14 dating, which is used to determine the age of objects that were once alive.
For example, suppose a wooden tool is discovered and its C-14 activity is determined
to have decreased to 65% of the original. How old is the object?
The half-life of C-14 is 5,730 yr. Substituting this into equation (2):

=
=
=×−−

k
k
k

5,730 yr ln 2/
5,730yr 0.693/
1.21 1041 yr

Substituting this rate constant into equation (1):

=− ×
−=−×
=

−−
−−

t
t
t

ln 65/100 (1.21 10 yr )
0.4308 (1.21 10 yr )
3,600 yr

41
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Mass–Energy Relationships


Whenever a nuclear decay or reaction takes place, energy is released. This energy may be
in the form of heat and light, gamma radiation, or kinetic energy of the expelled particle
and recoil of the remaining particle. This energy results from the conversion of a very small
amount of matter into energy. (Remember that in nuclear reactions there is no conservation
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