3.4.5.(b)(c)Part B
See solution for AB/BC 3.See solution for AB/BC 4.(a) The table below is constructed from the information given in
Question 5.f (5.1) ≈ 2 − 2(5.1 − 5) − (5.1 − 5)^2 + (5.1 − 5)^3≈ 2 − 0.2 − 0.005 + 0.001 = 1796.
Use Taylor’s Theorem around x = 0.g (x) ≈ 2 − 4x − 2x^2 + 8 x^3.