Barrons AP Calculus

(Marvins-Underground-K-12) #1
27.
(A)
(B)
(C)
(D)
(E)

28.
(A)
(B)
(C)
(D)
(E)

29.
(A)
(B)
(C)
(D)
(E)
30.

(A)
(B)
(C)
(D)

BC ONLY


In  Questions   27–30,  R   =   3   cos  t, 2   sin  t  is  the (position)  vector  x,  y   from
the origin to a moving point P(x, y) at time t.
A single equation in x and y for the path of the point is
x^2 + y^2 = 13
9 x^2 + 4 y^2 = 36
2 x^2 + 3 y^2 = 13
4 x^2 + 9 y^2 = 1
4 x^2 + 9 y^2 = 36
When t = 3, the speed of the particle is

2
3
π

The magnitude   of  the acceleration    when    t   =   3   is
2

3

π
At the point where t = , the slope of the curve along which the particle
moves is
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