Barrons AP Calculus

(Marvins-Underground-K-12) #1

Does converge or diverge?


SOLUTION:.


Therefore, this integral diverges.


It  can be  shown   that        converges   if  p   <   1   but diverges    if  p 1.    Figure

N7–25 shows an interpretation of in terms of areas where .


Only the first-quadrant area under to the left of x = 1 exists. Note that


.

BC  ONLY

Figure  N7–25
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