(a)
(b)
(a)
(b)
and
y = A − ce−kt.
Case II(b) can be solved similarly.
Example 18 __
According to Newton’s law of cooling, a hot object cools at a rate proportional
to the difference between its own temperature and that of its environment. If a
roast at room temperature 68°F is put into a 20°F freezer, and if, after 2 hours,
the temperature of the roast is 40°F:
What is its temperature after 5 hours?
How long will it take for the temperature of the roast to fall to 21°F?
SOLUTIONS:
This is an example of Case II(b) (the temperature is decreasing toward the
limiting temperature 20°F).
If R(t) is the temperature of the roast at time t, then
Since R(0) = 68°F, we have
Equation (*) in part (a) gives the roast’s temperature at time t. We must find t
when R = 21:
Example 19 __
Advertisers generally assume that the rate at which people hear about a product