Barrons AP Calculus

(Marvins-Underground-K-12) #1
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96  ft/sec
112 ft/sec
If the velocity of a car traveling in a straight line at time t is v(t), then the
difference in its odometer readings between times t = a and t = b is

the net displacement    of  the car’s   position    from    t   =   a   to  t   =   b
the change in the car’s position from t = a to t = b
the car’s average speed from t = a to t = b.
If an object is moving up and down along the y-axis with velocity v(t)
and s′(t) = v(t), then it is false that gives
s(b) − s(a)
the net distance traveled by the object between t = a and t = b
the total change in s(t) between t = a and t = b
the shift in the object’s position from t = a to t = b
the total distance covered by the object from t = a to t = b
Solutions of the differential equation y dy = x dx are of the form
x^2 − y^2 = C
x^2 + y^2 = C
y^2 = Cx 2
x^2 − Cy 2 = 0
x^2 = C − y^2

Find    the domain  of  the particular  solution    to  the differential    equation    in
Question 11 that passes through point (−2, 1).
x < 0
−2 ≤ x < 0

If      and y   =   1   when    x   =   4,  then
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