Barrons AP Calculus

(D)

(E)

99.

(A)

(B)

100.

(A)

(B)

(C)

(D)

(E)

101.

(A)

(B)

(C)

(D)

(E)

102.

(A)

(B)

(C)

(C)

(D)

(E)

40  cm^3

79  cm^3

BC ONLY QUESTIONS 99–108

A   particle    moves   counterclockwise    on  the circle  x   2   +   y   2   =   25  with    a

constant    speed   of  2   ft/sec. Its velocity    vector, v,  when    the particle    is  at  (3,

4), equals

Let R   =    a  cos kt, a   sin kt  be  the (position)  vector  from    the origin  to  a

moving  point   P(x,    y)  at  time    t,  where   a   and k   are positive    constants.  The

acceleration    vector, a,  equals

−k^2 R

a^2 k^2 R

−aR

−ak^2 a cos kt, a   sin kt

−R

The length  of  the curve   y   =   2x  between (0, 1)  and (2, 4)  is

3.141

3.664

4.823

5.000

7.199

The position    of  a   moving  object  is  given   by  P(t)    =   (3t,    et).    Its acceleration

is

undefined

constant    in  both    magnitude   and direction

constant    in  magnitude   only