(A)
(B)
(C)
(D)(A)
(B)
(C)
(D)(A)
(B)
(C)
(D)(A)
(B)is 6.10.
is 6.25.
does not exist, because f is not continuous.
does not exist, because f is not integrable.
If f ′(x) = 2 f(x) and f(2) = 1, then f(x) =
e^2 x − 4
e^2 x + 1 − e^4
e4 − 2x
ex(^2) − 4
If , then f ′(t) equals
The curve x^3 + x tan y = 27 passes through (3,0). Use the tangent line
there to estimate the value of y at x = 3.1. The value is
−2.7
−0.9