(a)
(b)
(c)
The object moves to the left when the velocity is negative,
namely, on the interval p < t < r. Use the calculator to solve (x
+ ex)(sin (x^2 )) = 0; then p = 1.772 and r = 2.507. The answer is
1.772 < t < 2.507.
At t = 2, the object is speeding up; because v(2) = −7.106 < 0
and a(2) = −30.897 < 0, the object is accelerating in the
direction of motion. (Note: You can use your calculator to find
both v(2) and a(2).)
.(Review Chapter 8)