(A)(D)(E)(C)(B) (f + 2 g)′(3) = f ′(3) + 2 g′(3) = 4 + 2(−1)(B) (f · g)′(2) = f (2) · g′(2) + g(2) · f ′(2) = 5(−2) + 1(3)(E)
marvins-underground-k-12
(Marvins-Underground-K-12)
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