Barrons AP Calculus

(C) The general solution    is  y   =   3   ln|x^2  −   4|  +   C.  The differential    equation

reveals  that    the     derivative  does    not     exist   for    x    =   ±2.     The

particular   solution    must    be  differentiable  in  an  interval    containing  the

initial value   x   =   −1, so  the domain  is  −2  <   x   <   2.

(A) The solution    curve   shown   is  y   =   ln  x,  so  the differential    equation    is  

.

(D).

(C) The equations   may be  rewritten   as      =   sin u   and y   =   1   −   2   sin^2 u,