31.32.Part B
(D) We solve the differential equation by separation:If s = 1 when t = 0, we have C = 1; hence, so when t = 1.(B)The roots of f(x) = x^2 − 4x − 5 = (x − 5)(x + 1) are x = −1 and 5. Since
areas
A and B are equal, therefore . Thus,