(D) G′(x) = f(3x − 1) · 3.(B) Since f changes from positive to negative at t = 3, G′ does also where
3 x − 1 = 3.(C) The limit by substitution is of the form
, so apply L’Hôpital’s Rule. You get , which is still of the
form , therefore apply L’Hôpital’s Rule again. The new
limit is by substitution is .(D) 2(3) + 2(0) + 2(4) + 2(1).(D)