SAT Mc Graw Hill 2011

(Marvins-Underground-K-12) #1
both of these are 3, b=3. Therefore, statement II
is true, and you can eliminate choice (A). To find
the average, just divide the sum by 20: ((1)(5)
+(2)(3) +(3)(3) +(4)(3) +(5)(3) +(6)(3))/20 =3.25,
so a=3.25. Therefore, statement I is not true, so
the answer is (B).


  1. B When a 30% solution and a 50% solution are
    combined, the concentration must be anywhere


between 30% and 50%, depending on how much
of each you added. It can’t be 50%, though,
because the 30% solution dilutes it.


  1. A If Set A were {0, 0, 10, 10, 10}, then its median,
    m,would be 10. Set B would be {2, 2, 12, 12, 12}.
    Inspection of Set B shows that it is a counterexam-
    ple to statements II and III, leaving (A) as a possible
    answer.


CHAPTER 9 / SPECIAL MATH PROBLEMS 341

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