Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

First, notice that we have two vertical asymptotes at x = 6 and x = −6. This means that the graph of the


derivative will also have vertical asymptotes at x = 6 and x = −6. Next, notice that the curve is always


decreasing. This means that the graph of the derivative will always be negative. Moving from left to right,


the graph starts out close to flat, so the derivative will be close to zero. Then, the graph gets very steep


and points downward, so the graph of the derivative will be negative and getting more negative. Then, we


have the asymptote x = −6. Next, the graph begins very steep and negative and starts to flatten out as we


approach the origin. At the origin, the slope of the graph is approximately − . This means that the graph


of the derivative will increase until it reaches (0, − ). Then, the graph starts to get steep again as we


approach the other asymptote x = 6. Thus, the graph will get more negative again. Finally, to the right of


the asymptote x = 6, the graph starts out steep and negative and flattens out, approaching zero. This means


that the graph of the derivative will start out very negative and will approach zero. If we now sketch the


derivative, it looks something like the following:

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