Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

The derivative is not defined at x = ±4. Setting the derivative equal to zero, we get


2(16    −   x)  =   2x^2

32  −   2x^2    =   2x^2

32  =   4x^2

x   =   ±

If  you’re  wondering   why we  don’t   use the negative    root,   it’s
because there is no such thing as a negative area.

Note that the domain of this function is −4 ≤ x ≤ 4, so these numbers serve as endpoints of the interval.
Let’s compare the critical values and the endpoints.


When    x   =   −4, y   =   0   and the area    is  0.

When    x   =   4,  y   =   0   and the area    is  0.

When    x   =    ,  y   =       and the area    is  16.

Thus, the maximum area occurs when x = and the area equals 16.


Try some of these solved problems on your own. As always, cover the answers as you work.


PROBLEM 1. A rectangular field, bounded on one side by a building, is to be fenced in on the other three
sides. If 3,000 feet of fence is to be used, find the dimensions of the largest field that can be fenced in.


Answer: First, let’s make a rough sketch of the situation.

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