PROBLEM 3. The radius of a sphere is measured to be 4 cm with an error of ±0.01 cm. Use differentials
to approximate the error in the surface area.
Answer: Now it’s time for the other differential formula. The formula for the surface area of a sphere is
S = 4πr^2
The formula says that dS = S′dr, so first, we find the derivative of the surface area, (S′ = 8πr) and plug
away.
dS = 8π rdr = 8π (4)(±0.01) = ± 1.0053
This looks like a big error, but given that the surface area of a sphere with radius 4 is approximately 201
cm^2 , the error is quite small.
PRACTICE PROBLEM SET 16
Use the differential formulas in this chapter to solve these problems. The answers are in Chapter 19.
1.Approximate .
2.Approximate .
3.Approximate tan 61°.
4.The side of a cube is measured to be 6 in. with an error of ±0.02 in. Estimate the error in the volume
of the cube.
5.When a spherical ball bearing is heated, its radius increases by 0.01 mm. Estimate the change in
volume of the ball bearing when the radius is 5 mm.
6.A cylindrical tank is constructed to have a diameter of 5 meters and a height of 20 meters. Find the
error in the volume if
(a)the diameter is exact, but the height is 20.1 meters; and
(b)the height is exact, but the diameter is 5.1 meters.