Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

Example 2: Suppose we have the function F(x) = sin t dt. Let’s evaluate this as x increases from 0 to


π. Obviously F(0) = 0 because there is no area under the curve. So, first, let’s find F . Graphically, we


are looking for the area under the curve y = sin t from t = 0 to t = . It looks like the following:


If we evaluate the integral, we get


F( ) = sin t dt = (−cos t) = −cos + cos 0 = 1 − ≈ 0.134


Now let’s find F( ). It looks like the following:

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