As with the natural logarithm, most of these integrals use u-substitution.
Example 14: Find ∫e^7 x dx.
Let u = 7x, du = 7dx, and du = dx. Then you have
∫e
7 x dx =
∫e
u du = eu + C
Substituting back, you get
e^7 x + C
In fact, whenever you see ∫ekx dx, where k is a constant, the integral is
∫e
kx dx = + C
Example 15: Find dx.
Let u = 3x^2 + 1, du = 6x dx, and du = x dx. The result is
Now it’s time to put the x’s back in.
Example 16: Find ∫esin x cos x dx.
Let u = sin x and du = cos x dx. The substitution here couldn’t be simpler.
∫^ e
u du = eu + C = esin x + C