Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

SOLUTIONS TO PRACTICE PROBLEM SET 1


1. 13

To  find    the limit,  we  simply  plug    in  8   for x:   (x^2   −   5x  −   11) =   (8^2    −(5)(8) −   11) =   13.

2.

To  find    the limit,  we  simply  plug    in  5   for x:      =       =   

.

3. 4

If  we  plug    in  3   for x,  we  get  ,  which   is  indeterminate.  When    this    happens,    we  try to  factor  the

expression   in  order   to  get     rid     of  the     problem     terms.  Here    we  factor  the     top     and     get:   

    =    .  Now we  can cancel  the term    x   −   3   to  get  (x +   1).

Notice  that    we  are allowed to  cancel  the terms   because x   is  not 3   but very    close   to  3.  Now we

can plug    in  3   for x:   (x +   1)  =   3   +   1   =   4.

4. + ∞

Here    we  are finding the limit   as  x   goes    to  infinity.   We  divide  the top and bottom  by  the highest

power   of  x   in  the expression, which   is: x^4 :       =    .  Next,

simplify    the top and bottom:  .  Now,    if  we  take    the limit   as  x   goes    to  infinity,

we  get     =       =   ∞.

5.

Here    we  are finding the limit   as  x   goes    to  infinity.   We  divide  the top and bottom  by  the highest
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