Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
this    page).  Therefore,  the derivative  is  −42x−8  −   .

10.

Use the Power   Rule    to  take    the derivative  of  each    term.   The derivative  of  x−5 =   −5x−6.  To  find

the derivative  of   ,  we  first   rewrite it  as  x−8.    The derivative  of  x−8 =   −8x−9.  Therefore,  the

derivative  is  −5x−6   −   8x−9    =   .


  1. 216 x^2 − 48x + 36


First,  expand  (6x^2   +   3)(12x  −   4)  to  get 72x^3   −   24x^2   +   36x −   12. Now,    use the Power   Rule    to
take the derivative of each term. The derivative of 72x^3 = 72(3x^2 ) = 216x^2 . The derivative of
24 x^2 = 24(2x) = 48x. The derivative of 36x = 36. The derivative of 12 = 0 (because the
derivative of a constant is zero). Therefore, the derivative is 216x^2 − 48x + 36.


  1. −6 − 36x^2 + 12x^3 − 5x^4 − 14x^6


First,  expand  (3  −   x   −   2x^3 )(6    +   x^4 )   to  get 18  −   6x  −   12x^3   +   3x^4    −   x^5     −   2x^7 .  Now,    use the Power
Rule to take the derivative of each term. The derivative of 18 = 0 (because the derivative of a
constant is zero). The derivative of 6x = 6. The derivative of 12x^3 = 12(3x^2 ) = 36x^2 . The
derivative of 34x^4 = 3(4x^3 ) = 12x^3 . The derivative of x^5 = 5x^4 . The derivative of 2x^7 = 2(7x^6 ) =
14 x^6 . Therefore, the derivative is −6 − 36x^2 + 12x^3 − 5x^4 − 14x^6.





Don’t   be  fooled  by  the powers. Each    term    is  a   constant    so  the derivative  is  zero.

14.

First,   expand  to  get     =   .   Next,

rewrite the terms   as: 4x−4    −   2x−5    −   6x−6.   Now,    use the Power   Rule    to  take    the derivative  of

each    term.   The derivative  of  4x−4    =   4(−4x−15)   =   −16x−5. The derivative  of  2x−5    =   2(−5x−6)    =

−10x−6. The derivative  of  6x−6    =   −36x−7. Therefore,  the derivative  is  −16x−5  +   10x−6   +   36x−7   =

.
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