Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
derivative  is  positive.   Therefore,  according   to  the second  derivative  test    (see    this    page),  the

perimeter   is  a   minimum at  r   =   .


  1. 1,352.786 meters


Let’s   think   about   the situation.  If  the swimmer swims   the whole   distance    to  the cottage,    she will
be traveling the entire time at her slowest speed. If she swims straight to shore first, minimizing
her swimming distance, she will be maximizing her running distance. Therefore, there should
be a point, somewhere between the cottage and the point on the shore directly opposite her,
where the swimmer should come on land to switch from swimming to running to get to the
cottage in the shortest time.

Let’s   draw    a   picture.

Let x   be  the distance    from    the point   on  the shore   directly    opposite    the swimmer to  the point

where   she comes   on  land.   We  have    two distances   to  consider.   The first   is  the diagonal    distance

that     the     swimmer     swims.  This    distance,   which   we’ll   call    D 1 ,   is  D 1 =  

. The second distance, which we’ll call D 2 , is simply D 2 =


1,800   −   x.  Remember    that    rate    ×   time    =   distance?   We’ll   use this    formula to  find    the total   time
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