Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
second  derivative, the value   is  negative,   so      is  a   maximum.    If  we  plug    x   =   −

into    the second  derivative, the value   is  negative,   so      is  a   maximum.    Now,    we

can draw    the curve.  It  looks   like    the following:


  1. Vertical asymptote at x = −8; Horizontal asymptote at y = 1; No maxima, minima, or points of
    inflection.


First,  notice  that    there   is  an  x-intercept at  x   =   3   and that    the y-intercept is   .  Next,   we

take    the derivative:     =       =    .  Next,   we  set the derivative

equal    to  zero    to  find    the     critical    points.     There   is  no  solution.   Next,   we  take    the     second
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