Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
2.

We  find    the average value   of  the function,   f(x),   on  the interval    [a, b]  using   the formula f(c)    =   

f(x)    dx. Here    we  are looking for the average value   of  f(x)    =       on  the interval    [0,

16].     Using   the     formula,    we  need    to  find    dx.     We  get     =  

= = = .

3. 1

We  find    the average value   of  the function,   f(x),   on  the interval    [a, b]  using   the formula f(c)    =   

f(x)    dx. Here    we  are looking for the average value   of  f(x)    =   2|x|    on  the interval    [−1,

1]. Using   the formula,    we  need    to  find        (2|x|)  dx. Recall  that    the absolute    value

function    must    be  rewritten   as  a   piecewise   function:|x|    =    .  Thus,   we  need    to  split   the

integral     into    two     separate    integrals   in  order   to  evaluate    it:     =  

x    dx.     We  get     =   =  

= 1.


  1. sin^2 x


We  find     the    derivative   of  an integral     using  the  Second  Fundamental    Theorem  of  Calculus:  

f(t)    dt  =   f(x).   We  get     sin^2 t dt  =   sin^2 x.


  1. 27 x^2 − 9x


We  find     the    derivative   of  an integral     using  the  Second  Fundamental    Theorem  of  Calculus:  
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