Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Next,    we  need    to  find    where   the     two     curves  intersect,  which   will    be  the     endpoints   of  the

region.  We  do  this    by  setting     the     two     curves  equal   to  each    other.  We  get    y^2 =   y    +   2.  The

solutions   are (4, 2)  and (1, −1).    Therefore,  in  order   to  find    the area    of  the region, we  need    to

evaluate    the integral        (y  +   2   −   y^2 )   dy. We  get     (y  +   2   −   y^2 )   dy  =       =   

− .

6. 4

We  find    the area    of  a   region  bounded by  f(y)    on  the right   and g(y)    on  the left    at  all points  of  the

interval    [c, d]  using   the formula  [f(y)− g(y)]   dy. Here,   f(y)    =   3   −   2y^2    and g(y)    =   y^2.

First,  let’s   make    a   sketch  of  the region.
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