Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Now we  isolate y.

y^3     =   3ex +   C

y   =   

Now we  solve   for C.  We  plug    in  x   =   0   and y   =   1.

1 =

C = −2

Therefore,  the equation    is  y   =   .


  1. y = 2x^2


We  solve   this    differential    equation    by  separation  of  variables.  We  want    to  get all of  the y

variables   on  one side    of  the equals  sign    and all of  the x   variables   on  the other   side.   We  can do

this    easily  by  dividing    both    sides   by  y^2     and multiplying both    sides   by  dx. We  get     =   .

Next,   we  integrate   both    sides.

Now we  isolate y.

Now we  solve   for C.  We  plug    in  x   =   1   and y   =   2.

C = 0
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