Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Now if  we  substitute  x   =   2,  we  get

= 4 + 2 +

Solving for y,  we  get

y   =   ±


  1. A In order to find the inflection point(s) of a polynomial, we need to find the values of x where
    its second derivative is zero.


First,  we  find    the second  derivative.

    =   20x^3   −   5x^4

    =   60x^2   −   20x^3

Now,    let’s   set the second  derivative  equal   to  zero    and solve   for x.

60 x^2  −   20x^3   =   0

20 x^2 (3   −   x)  =   0

x   =   3

This    is  the point   of  inflection. x   =   0   is  not a   point   of  inflection  because     does    not change

sign    there.

You can use a   calculator  on  this    part    of  the exam,   and you can use it  to  find    the inflection
point(s) of this graph.

Graphing    Calculator  (TI-83  and TI-84)

Press   the Y=  button, and enter   the following   values  to  the list:

Y 1     =   5X^4    −   X^5
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