G − = Cekt
Solving for G, we get
G = ekt +
Now, set G = 0. We get
0 = ekt +
Now, set G 0 = 300, and solve for ekt.
Take the log of both sides.
kt = ln
and t = ln
Now, we plug in the value for k that we got in part (a) above to get t ≈ 6.313 years.
- Consider the curve defined by y = x^4 + 4x^3.
(a) Find the equation of the tangent line to the curve at x = −1.
If we want to find the equation of the tangent line, first we need to find the y-coordinate that
corresponds to x = −1.
y = (−1)^4 + 4(−1)^3 = 1 − 4 = −3
Next, we need to find the derivative of the curve at x = −1.
