Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Evaluate:       4cos(2x)    dx  =    2  sin(2x)     =   0.


  1. B This is not a related-rate problem; this is a differential equation! It just happens to involve a
    rate.


Step    1:  If  we  translate   the first   sentence    into    an  equation    we  get     =   kR.

Put all of  the terms   that    contain an  R   on  the left    of  the equals  sign    and all of  the terms   that
contain a t on the right-hand side.

    =   k   dt

Step    2:  Integrate   both    sides.

∫ = k^ dt


Step    3:  If  we  solve   this    for R,  we  get R   =   Cekt    (see    the unit    on  Differential    Equations).

Now we  need    to  solve   for C   and k.  First,  we  solve   for C   by  plugging    in  the information that    the
radius is 4 initially. This means that R = 4 when t = 0.

If  4   =   Ce^0 ,  then    C   =   4

Next,   we  solve   for k   by  plugging    in  the information that    R   =   10  when    t   =   2.

10  =   4e^2 k

    =   e^2 k

ln  =   2k

    ln  =   k

Step    4:  Now we  have    our final   equation:   R   =   4.

If  we  plug    in  t   =   3   we  get R   =   4   ≈   15.81.


  1. A We use the Second Fundamental Theorem of Calculus to find the derivative of the integral. In

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