Cracking The Ap Calculus ab Exam 2018

(D)y    =   2x^3

15.Find .

(A)−

(B) 0

(C)

(D) 1

16.∫ 18 x^2 sec^2 (3x^3 ) dx =

(A)2tan^2 (3x^3 )   +   C

(B)cot(3x^3 )   +   C

(C)tan(3x^3 )   +   C

(D)2    tan(3x^3 )  +   C

17.What is the equation of the line normal to the curve y = x^3 + 2x^2 −5x + 7 at x = 1 ?

(A)y    =   − x +   

(B)y    =   2x  +   3

(C)y    =   − x −   

(D)y    =   −2x −   

18.

(A) 0