Now, plug into the equation above to get
17.321 = −10(−5) and ≈ 2.887
- C = . At t = . At this time, x = 4 and y = .
Thus, equation for the tangent line is (y − ) = − (x − 4) or y = −.
- B First, let’s take the derivative: h′(t) = 100 − 32t = 0.
Now, we set it equal to zero and solve for t: 100 − 32t = 0.
t =
Now, to solve for the maximum height, we simply plug t = back into the original equation
for height.
By the way, we know that this is a maximum not a minimum because the second derivative is
−32, which means that the critical value will give us a maximum not a minimum.
