Barrons SAT Subject Test Chemistry, 13th Edition
marvins-underground-k-12
(Marvins-Underground-K-12)
2020-12-01 17:24:28 UTC
#1
(T, T, CE) Four grams of ice would require 4 × 80 cal/g = 320 cal or 4 ×
3.34 × 10^2 J/g = 1.34 × 10^3 J to melt the ice.
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