Barrons SAT Subject Test Chemistry, 13th Edition

45. (E) The reaction is:

The gram-molecular mass of calcium carbonate is 100 g. Then 150 g =

or 1.5 mol of calcium carbonate. According to the equation, 1 mol

of CaCO 3 yields 1 mol of carbon dioxide, so 1.5 mol of CaCO 3 yields

1.5 mol of CO 2.

The gram-molecular mass of CO 2 = 44 g:

1.5 mol of CO 2 = 1.5 × 44 g = 66 g CO 2