IMPLEMENTATION: Solve the equation:
3
4ð 20 þxÞ¼ 1 ð 20 xÞ41
13
41
ð 20 þxÞ¼4
1
ð 20 xÞ3 ð 20 þxÞ¼ 4 ð 20 xÞ60 þ 3 x¼ 80 4 x60 þ 3 xþ 4 x¼ 80 4 xþ 4 x60 þ 7 x¼ 8060 60 þ 7 x¼ 80 607 x¼ 2071 x
7¼
20
7
x¼ 26
7
miles per hourEVALUATION: Check to see if the distance going downstream is equal to
the distance going upstream usingD¼RT.
DownstreamD¼3
4
ð 20 þxÞ¼
3
4
20 þ 26
7
¼
3
4
22
6
7
¼ 17
1
7
milesUpstreamD¼ 1 ð 20 xÞ¼ 120 26
7
¼ 17
1
7
milesLESSON 13 Solving Distance Problems 141