(b) There are six outcomes in the sample space and there are
two outcomes that are greater than 4, that is, 5 and 6; hence,
P(a number greater than 4)¼^26 ¼^13.
(c) There are six outcomes in the sample space and five numbers less
than six; hence,P(a number less than six)¼^56.
(d) There are six outcomes in the sample space and no numbers are
greater than six; hence,P(a number greater than six)¼^06 ¼0.2.
(a) There are 36 outcomes in the sample space and there are five ways
to get a sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), and (6, 2); hence,
P(sum of 8)¼ 365.
(b) There are 36 outcomes in the sample space and six ways to get
doubles: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), and (6, 6); hence
P(doubles)¼ 366 ¼^16.
(c) There are 36 outcomes in the sample space and there are 3 ways
of getting a sum greater than ten, that is, a sum of 11 or 12: (5, 6),
(6, 5), and (6, 6). Hence,P(sum greater than 10)¼ 363 ¼ 121.
(d) There are 36 outcomes in the sample space and six ways to get a
sum of 4, 3, or 2: (1, 3), (2, 2), (3, 1), (1, 2), (2, 1), and (1, 1).
Hence,P(sum less than 3)¼ 366 ¼^16.3.
(a) There are 52 outcomes in the sample space and one six of
diamonds; hence,P(six of diamonds)¼ 521.
(b) There are 52 outcomes in the sample space and four queens;
hence,P(queen)¼ 524 ¼ 131.
(c) There are 52 outcomes in the sample space and 13 hearts; hence,
P(heart)¼^1352 ¼^14.
(d) There are 52 outcomes in the sample space and 13 clubs and 13
spades; hence,P(club or spade)¼^1352 þ^13 ¼^2652 ¼^12.
(e) There are 52 outcomes in the sample space and 26 red cards (13
diamonds and 13 hearts); hence,P(red card)¼^2652 ¼^12.- The sample space for three children is
BBB GGB
BBG GBG
BGB BGG
GBB GGG274 LESSON 22 Word Problems in Probability