Cracking The SAT Premium

(Marvins-Underground-K-12) #1

positive integer, so this doesn’t work. Try a new median. If x = 4, then the set is {2, 3, 4 (x),


5, 7), with a median of 4. However, the mean is = 5.25, not 4, so this


doesn’t work. If x is 6 or greater, the set would either be {2, 3, 5, 6 (x), 7} or {2, 3, 5, 7,


x}. In either case, the median is 5. Set up the average equal to the median of 5:


    =   5.  Multiply    both    sides   by  5   and combine like    terms:  17  +   x   =   25.

Subtract 17 from both sides, and you find that x = 8.

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