CK-12-Physics-Concepts - Intermediate

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 19. Electrical Circuits


The current through each resistor can be found using the voltage drop and the resistance of that resistor:


I 1 =


VT


R 1


=


90 .V


60 .Ω


= 1. 5 A I 2 =


VT


R 2


=


90 .V


30 .Ω


= 3. 0 A I 3 =


VT


R 3


=


90 .V


30 .Ω


= 3. 0 A


The total current through the circuit would be the sum of the three currents in the individual resistors.


IT=I 1 +I 2 =I 3 = 1. 5 A+ 3. 0 A+ 3. 0 A= 7. 5 A


The equivalent resistance for this circuit is found using the equation above.


1


RT


=


1


R 1


+


1


R 2


+


1


R 3


=


1


60 .Ω


+


1


30 .Ω


+


1


30 .Ω


=


1


60 .Ω


+


2


60 .Ω


+


2


60 .Ω


=


5


60 .Ω


RT=^60. 5 Ω= 12 Ω


The equivalent resistance for the circuit could also be found by using the total voltage drop and the total current.


RT=VITT=^907. 5 .ΩA= 12 Ω


Summary



  • Parallel electrical circuits have multiple paths the current may take.

  • VT=V 1 =V 2 =V 3.

  • IT=I 1 +I 2 +I 3.

  • R^1 T =R^11 =R^12 +R^13.


Practice


Questions


http://www.youtube.com/watch?v=apHkG4T6QHM


MEDIA


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Follow up questions:

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