17.4. Resistors in Series and Parallel http://www.ck12.org
Answer:
After the current passes through the 10Ωresistor, there is a junction in the circuit where the current splits up. The
currentI 12 passes through the 12Ωresistor, and the currentI 24 passes through the 24Ωresistor. The 12Ωresistor and
24 Ωresistor are in parallel and experience the same voltage drop.
The equivalent resistance for the parallel resistors is
Requivalent=RR 11 +RR^22 =(^1212 ΩΩ+)(^2424 ΩΩ)= 8 Ω
The circuit can be redrawn as seen below.
The 10Ωresistor and the 8Ωresistor are in series. The equivalent resistance of the circuit is therefore,
Requivalent= 10 Ω+ 8 Ω= 18 Ω
The final circuit is drawn below.