http://www.ck12.org Chapter 19. Thermodynamics and Heat Engines
FIGURE 19.2
Illustration x-direction atom from above.
According to Newton’s second law, the force imparted by the single particle on the wall is
F=
∆p
∆t
= 2 mvx×
vx
2 L
=
mvx^2
L
Now, since there aren(a very large number) atoms present, the net force imparted on the wall will be
Fnet=n×
m(vx^2 )avg
L
Where thevx^2 is averaged over allnatoms.
Now let us attempt to relate this to the state variables we considered last chapter. Recall that pressure is defined as
force per unit area:
P=
F
A
Since the area of the wall in question isL^2 , thepressureexerted by the gas atoms on it will equal:
Pnet=
Fnet
A
=n
m(vx^2 )avg
L×L^2
=n
m(vx^2 )avg
L^3
Since, for a cubical box, volumeV=L^3 , the formula above can be reduced to:
Pnet=n
m(vx^2 )avg
V
or,
PnetV=nm(vx^2 )avg [1]